Critical angle of incidence for a pair of optical media is 45°. The refractive indices of first and second media are in the ratio:

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Solution

Q.
Critical angle of incidence for a pair of optical media is 45°. The refractive indices of first and second media are in the ratio: [2024]

1 $1 : \sqrt{2}$

2 $1 : 2$

3 $\sqrt{2} : 1$

4 $2 : 1$

Ans.
(3)

We know

$\sin c = \frac{n_{2}}{n_{1}} \Rightarrow \frac{n_{1}}{n_{2}} = \frac{1}{\sin c}$

$\Rightarrow \frac{n_{1}}{n_{2}} = \frac{1}{\sin 45} = \frac{\sqrt{2}}{1}$

$n_{1} : n_{2} = \sqrt{2} : 1$

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