∫cos2x-cos2θcosx-cosθdx is equal to:
(1)
Ans. 2(sinx+xcosθ)+C
Explanation:
Let I=∫cos2x-cos2θcosx-cosθdx
=∫(2cos2x-1)-(2cos2θ-1)cosx-cosθdx
=2∫cos2x-cos2θcosx-cosθdx
=2∫(cosx-cosθ)(cosx+cosθ)cosx-cosθdx
=2∫(cosx+cosθ)dx
=2(sinx+xcosθ)+C