7 e 7 x + 5 ? d x =

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Solution

Q.
$\int 7 e^{7 x + 5} d x =$

1 $7 (7 e^{7 x + 5}) + C$

2 $\frac{7 e^{7 + 5}}{5} + C$

3 $e^{7 x + 5} + C$

4 $\frac{7 e^{7 + 5}}{7 x + 5} + C$

Ans.
(3)

Ans. $e^{7 x + 5} + C$

Explanation:

$\int 7 e^{7 x + 5} d x = 7 \cdot \frac{e^{7 x + 5}}{7} + C = e^{7 x + 5} + C$

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