Consider the transition metal ions , , and and all form low spin octahedral complexes. The correct decreasing order of unpaired electrons in their respective -orbitals of the complexes is [2026]

Question

Consider the transition metal ions ${Mn}^{3 +}$ , ${Cr}^{3 +}$ , ${Fe}^{3 +}$ and ${Co}^{3 +}$ and all form low spin octahedral complexes. The correct decreasing order of unpaired electrons in their respective $d$ -orbitals of the complexes is [2026]

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(1)

${Co}^{3 +} \to 3 d^{6} \Rightarrow t_{2 g}^{2, 2, 2} e_{g}^{0, 0}, unpaired electron = 0$

${Fe}^{3 +} \to 3 d^{5} \Rightarrow t_{2 g}^{2, 2, 1} e_{g}^{0, 0}, unpaired electron = 1$

${Cr}^{3 +} \to 3 d^{3} \Rightarrow t_{2 g}^{1, 1, 1} e_{g}^{0, 0}, unpaired electron = 3$

${Mn}^{3 +} \to 3 d^{4} \Rightarrow t_{2 g}^{2, 1, 1} e_{g}^{0, 0}, unpaired electron = 2$

Solution

Q.
Consider the transition metal ions ${Mn}^{3 +}$ , ${Cr}^{3 +}$ , ${Fe}^{3 +}$ and ${Co}^{3 +}$ and all form low spin octahedral complexes. The correct decreasing order of unpaired electrons in their respective $d$ -orbitals of the complexes is [2026]

1 ${Cr}^{3 +} > {Mn}^{3 +} > {Fe}^{3 +} > {Co}^{3 +}$

2 ${Mn}^{3 +} > {Fe}^{3 +} > {Co}^{3 +} > {Cr}^{3 +}$

3 ${Fe}^{3 +} > {Co}^{3 +} > {Mn}^{3 +} > {Cr}^{3 +}$

4 ${Cr}^{3 +} > {Fe}^{3 +} > {Co}^{3 +} > {Mn}^{3 +}$

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Solution

Q. Consider the transition metal ions Mn3+, Cr3+, Fe3+ and Co3+ and all form low spin octahedral complexes. The correct decreasing order of unpaired electrons in their respective d-orbitals of the complexes is [2026]

1 Cr3+>Mn3+>Fe3+>Co3+

2 Mn3+>Fe3+>Co3+>Cr3+

3 Fe3+>Co3+>Mn3+>Cr3+

4 Cr3+>Fe3+>Co3+>Mn3+