On heating a mixture of common salt and in equal amount along with concentrated in a test tube, a gas is evolved. Formula of the gas evolved and oxidation state of the central metal atom in the gas re

Question

On heating a mixture of common salt and $K_{2} {Cr}_{2} O_{7}$ in equal amount along with concentrated $H_{2} {SO}_{4}$ in a test tube, a gas is evolved. Formula of the gas evolved and oxidation state of the central metal atom in the gas respectively are: [2026]

Smart Achievers · Accepted Answer

(3)

$4 NaCl + K_{2} {Cr}_{2} O_{7} + 6 H_{2} {SO}_{4}$

$⟶ 2 {KHSO}_{4} + \underset{(Chromyl chloride)}{2 {CrO}_{2} {Cl}_{2}} + 4 {NaHSO}_{4} + 3 H_{2} O$

$In Chromyl chloride Cr is in + 6 oxidation state.$

Solution

Q.
On heating a mixture of common salt and $K_{2} {Cr}_{2} O_{7}$ in equal amount along with concentrated $H_{2} {SO}_{4}$ in a test tube, a gas is evolved. Formula of the gas evolved and oxidation state of the central metal atom in the gas respectively are: [2026]

1 $C r_{2} O_{2} C l_{2} and + 6$

2 $C r O_{2} C l_{2} and + 5$

3 $C r O_{2} C l_{2} and + 6$

4 $C r_{2} O_{2} C l_{2} and + 3$

Ans.
(3)

$4 NaCl + K_{2} {Cr}_{2} O_{7} + 6 H_{2} {SO}_{4}$

$⟶ 2 {KHSO}_{4} + \underset{(Chromyl chloride)}{2 {CrO}_{2} {Cl}_{2}} + 4 {NaHSO}_{4} + 3 H_{2} O$

$In Chromyl chloride Cr is in + 6 oxidation state.$

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Solution

Q. On heating a mixture of common salt and K2Cr2O7 in equal amount along with concentrated H2SO4 in a test tube, a gas is evolved. Formula of the gas evolved and oxidation state of the central metal atom in the gas respectively are: [2026]

1 Cr2O2Cl2​ and +6

2 CrO2Cl2​ and +5

3 CrO2Cl2​ and +6

4 Cr2O2Cl2​ and +3

Ans. (3) 4NaCl+K2Cr2O7+6H2SO4 ⟶2KHSO4+2CrO2Cl2(Chromyl chloride)+4NaHSO4+3H2O In Chromyl chloride Cr is in +6 oxidation state.