Consider the reactions. Why thiosulphate (reductant) react differently with iodine & Bromine?

Question

Consider the reactions.

$2 S_{2} {O_{3}^{2 -}}_{(a q)} + {I_{2}}_{(s)} ⟶ S_{4} {O_{6}^{2 -}}_{(a q)} + 2 {I^{-}}_{(a q)}$

$S_{2} {O_{3}^{2 -}}_{(a q)} + 2 B {r_{2}}_{(l)} + 5 H_{2} O_{(l)} ⟶ 2 S {O_{4}^{2 -}}_{(a q)} + 4 B {r^{-}}_{(a q)} + 10 {H^{+}}_{(a q)}$

Why thiosulphate (reductant) react differently with iodine & Bromine?

Smart Achievers · Accepted Answer

(3)

$Oxidation power order: F_{2} > {Cl}_{2} > {Br}_{2} > I_{2}$

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