The average oxidation number of Br in is ‘x’ and the average oxidation number of C in is ‘y’ then

Question

The average oxidation number of Br in $B r_{3} O_{8}$ is ‘x’ and the average oxidation number of C in $C_{3} O_{2}$ is ‘y’ then $\frac{x}{y} =$ _______

Smart Achievers · Accepted Answer

(4)

$\frac{\frac{16}{3}}{\frac{4}{3}} = 4$

Solution

Q.
The average oxidation number of Br in $B r_{3} O_{8}$ is ‘x’ and the average oxidation number of C in $C_{3} O_{2}$ is ‘y’ then $\frac{x}{y} =$ _______

Ans.
(4)

$\frac{\frac{16}{3}}{\frac{4}{3}} = 4$

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Solution

Q. The average oxidation number of Br in Br3O8 is ‘x’ and the average oxidation number of C in C3O2 is ‘y’ then xy=_______

Ans. (4) 16343=4

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Q.
The average oxidation number of Br in $B r_{3} O_{8}$ is ‘x’ and the average oxidation number of C in $C_{3} O_{2}$ is ‘y’ then $\frac{x}{y} =$ _______

Ans.
(4)

$\frac{\frac{16}{3}}{\frac{4}{3}} = 4$