An electric charge is placed at origin (0, 0) m of X-Y co-ordinate system. Two points P and Q are situated at and respectively. The potential difference between the points P and Q will be

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Solution

Q.
An electric charge $10^{- 6} μ C$ is placed at origin (0, 0) m of X-Y co-ordinate system. Two points P and Q are situated at $(\sqrt{3}, \sqrt{3}) m$ and $(\sqrt{6}, 0) m$ respectively. The potential difference between the points P and Q will be [2024]

1 $\sqrt{3} V$

2 $\sqrt{6} V$

3 $0 V$

4 $3 V$

Ans.
(3)

Potential difference $= \frac{K Q}{r_{1}} - \frac{K Q}{r_{2}}$

   $r_{1} = \sqrt{{(\sqrt{3})}^{2} + {(\sqrt{3})}^{2}}$

   $r_{2} = \sqrt{{(\sqrt{6})}^{2} + 0}$

As $r_{1} = r_{2} = \sqrt{6} m$

  So potential difference = 0.

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