The electric potential at the surface of an atomic nucleus of radius cm is

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Solution

Q.
The electric potential at the surface of an atomic nucleus $(z = 50)$ of radius $9 \times 10^{- 13}$ cm is ______ $\times 10^{6}$ V [2024]

Ans.
(8) Potential = $\frac{k Q}{R} = \frac{k . Z e}{R}$

$= \frac{9 \times 10^{9} \times 50 \times 1.6 \times 10^{- 19}}{9 \times 10^{- 13} \times 10^{- 2}} = 8 \times 10^{6} V$

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