At the centre of a half ring of radius R = 10 cm and linear charge density 4 n , the potential is . The value of x is

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Solution

Q.
At the centre of a half ring of radius R = 10 cm and linear charge density 4 n $C m^{- 1}$ , the potential is $x π$ $V$ . The value of $x$ is _______ . [2024]

Ans.
(36) Potential at centre of half ring

$V = \frac{K Q}{R} = \frac{K λ π R}{R}$

$V = K λ π \Rightarrow V = 9 \times 10^{9} \times 4 \times 10^{- 9} π$

$\Rightarrow$ $V = 36 π V$

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