According to Bohr model, magnetic field at centre (at the nucleus) of a hydrogen atom due to motion of electron in the nth orbit is proportional to

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Solution

Q.
According to Bohr model, magnetic field at centre (at the nucleus) of a hydrogen atom due to motion of electron in the nth orbit is proportional to

1 $\frac{1}{n^{3}}$

2 $\frac{1}{n^{5}}$

3 $n^{5}$

4 $n^{3}$

Ans.
(2)

$B = \frac{μ_{0} i}{2 r}$ ; magnetic field at centre of hydrogen atom i.e. at nucleus.

$i = \frac{e}{T} = e f \propto \frac{Z^{2}}{n^{3}}$

$r \propto \frac{n^{2}}{Z}$

$B \propto \frac{i}{r} \propto \frac{Z^{3}}{n^{5}}$

$B \propto \frac{1}{n^{5}}$

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