The minimum energy of an electron necessary for ionization of an atom of hydrogen, is equal to . Suppose that a hydrogen atom and helium atom both in ground state collide inelastically so that hydrogen atom is ionized. If the hydrogen was at rest and heli

Question

The minimum energy of an electron necessary for ionization of an atom of hydrogen, is equal to $W_{0}$ . Suppose that a hydrogen atom and helium atom both in ground state collide inelastically so that hydrogen atom is ionized. If the hydrogen was at rest and helium was moving with at least energy of $x W_{0}$ , find the value of $x$ .

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(5)

$Possible loss = \frac{1}{2} \frac{4 m}{5} V^{2} = W_{0}$

$K E_{H e} = \frac{1}{2} 4 m V^{2} = 5 W_{0}$

Solution

Ans.
(5)

$Possible loss = \frac{1}{2} \frac{4 m}{5} V^{2} = W_{0}$

$K E_{H e} = \frac{1}{2} 4 m V^{2} = 5 W_{0}$

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Solution

Ans. (5) Possible loss=124m5V2=W0 KEHe=124mV2=5W0

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Ans.
(5)

$Possible loss = \frac{1}{2} \frac{4 m}{5} V^{2} = W_{0}$

$K E_{H e} = \frac{1}{2} 4 m V^{2} = 5 W_{0}$