A series LCR circuit with R = 20 , L = 1.6 H and C = 40 is connected to a variable frequency a.c. source. The inductive reactance at resonant frequency is

Question

A series LCR circuit with R = 20 $Ω$ , L = 1.6 H and C = 40 $μF$ is connected to a variable frequency a.c. source. The inductive reactance at resonant frequency is _____ $Ω$ . [2026]

Smart Achievers · Accepted Answer

(200)

$For resonance:$

$Ω$

$Inductive reactance, X_{L} = ω L = \frac{1}{8 \times 10^{- 3}} \times 1.6 = 200 Ω$

Solution

Q.
A series LCR circuit with R = 20 $Ω$ , L = 1.6 H and C = 40 $μF$ is connected to a variable frequency a.c. source. The inductive reactance at resonant frequency is _____ $Ω$ . [2026]

Ans.
(200)

$For resonance:$

$ω = \frac{1}{\sqrt{L C}} = \frac{1}{\sqrt{1.6 \times 40 \times 10^{- 6}}} = \frac{10^{3}}{8} = 125$

$Inductive reactance, X_{L} = ω L = \frac{1}{8 \times 10^{- 3}} \times 1.6 = 200 Ω$

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Solution

Q. A series LCR circuit with R = 20 Ω, L = 1.6 H and C = 40 μF is connected to a variable frequency a.c. source. The inductive reactance at resonant frequency is _____ Ω. [2026]

Ans. (200) For resonance: ω=1LC=11.6×40×10-6=1038=125 Inductive reactance, XL=ωL=18×10-3×1.6=200 Ω

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Q.
A series LCR circuit with R = 20 $Ω$ , L = 1.6 H and C = 40 $μF$ is connected to a variable frequency a.c. source. The inductive reactance at resonant frequency is _____ $Ω$ . [2026]

Ans.
(200)

$For resonance:$

$ω = \frac{1}{\sqrt{L C}} = \frac{1}{\sqrt{1.6 \times 40 \times 10^{- 6}}} = \frac{10^{3}}{8} = 125$

$Inductive reactance, X_{L} = ω L = \frac{1}{8 \times 10^{- 3}} \times 1.6 = 200 Ω$