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Solution


Q.

A LCR circuit is at resonance for a capacitor C, inductance L and resistance R. Now the value of resistance is halved keeping all other parameters the same. The current amplitude at resonance will be now                 [2024]
1 halved  
2 Zero  
3 same  
4 double  

Ans.

(4)       

           At resonance: Z = R

           So I∝1R

           R→halved⇒I=2I,I becomes doubled.