Q.

A series LCR circuit is subjected to an ac signal of 200 V, 50 Hz. If the voltage across the inductor (L = 10 mH) is 31.4 V, then the current in this circuit is    [2024]

1 68 A  
2 63 A  
3 10 A  
4 10 mA  

Ans.

(3)    

         Voltage across inductor VL=IXL

         31.4=I[Lω]

         31.4=I[L(2πf)]

         31.4=I[10×10-3(2×3.14)×50]I=10A