A point charge of 10 is placed at the origin. At what location on the X-axis should a point charge of 40 be placed so that the net electric field is zero at = 2 cm on the X-axis? [2023]

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Solution

Q.
A point charge of 10 $μC$ is placed at the origin. At what location on the X-axis should a point charge of 40 $μC$ be placed so that the net electric field is zero at $x$ = 2 cm on the X-axis [2023]

1 $x = -4 cm$

2 $x = 4 cm$

3 $x = 8 cm$

4 $x = 6 cm$

Ans.
(4)

$E_{P} = \frac{K \times 10}{2^{2}} - \frac{K \times 40}{{(x_{0} - 2)}^{2}} = 0$

$\frac{1}{2} = \frac{2}{x_{0} - 2}$

$x_{0} - 2 = 4 \Rightarrow x_{0} = 6 cm$

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