A point charge is placed at the origin. Another point charge is placed at cm. The charge of a proton is . [2023]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
A point charge $q_{1} = 4 q_{0}$ is placed at the origin. Another point charge $q_{2} = - q_{0}$ is placed at $x = 12$ cm. The charge of a proton is $q_{0}$ . The proton is placed on the $x$ -axis so that the electrostatic force on the proton is zero. In this situation, the position of the proton from the origin is ________ cm. [2023]

Ans.
(24)

$\frac{q_{0}}{x^{2}} = \frac{4 q_{0}}{{(x + 12)}^{2}}$

$x + 12 = 2 x \Rightarrow x = 12$

$Distance from origin = x + 12 = 24 cm$

Want Us to Email you About Special Offers & Updates?