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Solution


Q.

A 10 μC charge is divided into two parts and placed at 1 cm distance so that the repulsive force between them is maximum. The charges of the two parts are       [2023]
1 9 μC, 1 μC  
2 5 μC, 5 μC  
3 7 μC, 3 μC  
4 8 μC, 2 μC  

Ans.

(2)

Divide q=10 μC into two parts x and q-x.

F=Kx(q-x)r2

For F to be maximum

dFdx=Kr2(q-2x)=0⇒x=q2