A parallel beam of monochromatic light of wavelength 600 nm passes through a single slit of 0.4 mm width. Angular divergence corresponding to the second order minima would be ____ × 10?³ rad.

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Solution

Q.
A parallel beam of monochromatic light of wavelength 600 nm passes through a single slit of 0.4 mm width. Angular divergence corresponding to the second order minima would be ____ × $10^{- 3}$ rad. [2024]

Ans.
(6)    $\sin θ ≃ θ ≃ \frac{2 λ}{b}$

   $= \frac{2 \times 600 \times 10^{- 9}}{4 \times 10^{- 4}} = 3 \times 10^{- 3} rad$

  Total divergence = $(3 + 3) \times 10^{- 3} = 6 \times 10^{- 3} r a d$

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