The diffraction pattern of a light of wavelength 400 nm diffracting from a slit of width 0.2 mm is focused on the focal plane of a convex lens of focal length 100 cm. The width of the 1st secondary maxima will be

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Solution

Q.
The diffraction pattern of a light of wavelength 400 nm diffracting from a slit of width 0.2 mm is focused on the focal plane of a convex lens of focal length 100 cm. The width of the 1st secondary maxima will be [2024]

1 2 mm

2 2 cm

3 0.02 mm

4 0.2 mm

Ans.
(1)

$width of secondary maxima = \frac{λ f}{a}$

$= \frac{400 \times 10^{- 9} \times 1}{0.2 \times 10^{- 3}} = \frac{2 \times 10^{- 7}}{10^{- 4}} = 2 \times 10^{- 3} m = 2 mm$

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