A microwave of wavelength 2.0 cm falls normally on a slit of width 4.0 cm. The angular spread of the central maxima of the diffraction pattern obtained on a screen 1.5 m away from the slit will be

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Solution

Q.
A microwave of wavelength 2.0 cm falls normally on a slit of width 4.0 cm. The angular spread of the central maxima of the diffraction pattern obtained on a screen 1.5 m away from the slit will be [2024]

1 30°

2 15°

3 60°

4 45°

Ans.
(3)

$d \sin θ = λ (Half angular speed)$

$\sin θ = \frac{λ}{d} = \frac{2 \times 10^{- 2}}{4 \times 10^{- 2}} = \frac{1}{2} \Rightarrow θ = 30 °$

$Full angular speed = 2 θ = 60 °$

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