Q.

6x10+4x3x10-3x4-1dx,  x>0= _____________  (c is constant of integration)

1 x10-3x4-1x2+c  
2 2x10-3x4-1x2+c  
3 2x10-3x4-1+c  
4 x10-3x4+C  

Ans.

(2)

6x10+4x5x6-3-x-4dx=6x5+4x-5x6-3-x-4dx

x6-3-x-4=t    (6x5+4x-5)dx=dt