∫6x10+4x3x10-3x4-1 dx, x>0= _____________ (c is constant of integration)
(2)
∫6x10+4x5x6-3-x-4dx=∫6x5+4x-5x6-3-x-4dx
x6-3-x-4=t (6x5+4x-5)dx=dt