Q 1 :

Each of the angles β and γ that a given line makes with the positive y-axes and z-axes, respectively, is half of the angle that this line makes with the positive x-axes. Then the sum of all possible values of the angle β is          [2025]

  • π

     

  • π2

     

  • 3π4

     

  • 3π2

     

(3)

Let the line makes angle α with positive x-axis, then β=α2 and γ=α2

Now, cos2α+cos2β+cos2γ=1

 cos2α+2cos2α2=1

 cos2α+cosα=0

 cosα(cosα+1)=0

  cosα=0,1 α=π2,π

Now, β=α2  β=π4,π2

So, required sum =π4+π2=3π4.



Q 2 :

Let A(x, y, z) be a point in xy-plane, which is equidistant from three points (0, 3, 2), (2, 0, 3) and (0, 0, 1). Let B = (1, 4, –1) and C = (2, 0, –2). Then among the statements

(S1) : ABC is an isosceles right angled triangle, and

(S2) : the area of ABC is 922.

  • only (S1) is true

     

  • both are false

     

  • both are true

     

  • only (S2) is true

     

(1)

Given, A(x, y, z) be a point in xy-plane. Let the point P(0, 3, 2), Q(2, 0, 3) and R(0, 0, 1)

The distance of the point AP = AQ = AR

 (x0)2+(y3)2+(z2)2

     =(x2)2+(y0)2+(z3)2

     =(x0)2+(y0)2+(z1)2

In xy-plane, z = 0

So, x24x+y2+9+4=x2+y2+1  4x+13=1  x=3

And x2+y26y+9+4=x2+y2+1  y=2

So, A(3, 2, 0), B(1, 4, –1) and C(2, 0, –2).

In ABC

AB=1+4+4=3, BC=1+16+1=18, CA=1+4+4=3

So, AB = AC and AB2+AC2=(BC)2

   ABC is an isosceles right angled triangle.

So, (S1) is true.

Also, Area of ABC=12×(Base)(Height)=12×3×3=92

So, (S2) is false.



Q 3 :

One vertex of a rectangular parallelepiped is at the origin O and the lengths of its edges along x,y and z axes are 3, 4 and 5 units respectively. Let P be the vertex (3, 4, 5). Then the shortest distance between the diagonal OP and an edge parallel to z-axis, not passing through O or P is         [2023]

  • 125

     

  • 1255

     

  • 125

     

  • 125

     

(1)

Equation of line OP,x-03-0=y-04-0=z-05-0
i.e., x3=y4=z5

Now, equation of edge parallel to z-axis passing through (3,0,5) and having direction ratios <0,0,1> is

x-30=y-00=z-51

Here, a1=(0,0,0),a2=(3,0,5);b1=(3,4,5),b2=(0,0,1)

So, a2-a1=3i^+5k^

b1×b2=|i^j^k^345001|=i^(4-0)-j^(3-0)+k^(0-0)=4i^-3j^

   Required shortest distance=|(3i^+5k^)·(4i^-3j^)|4i^-3j^||

=1216+9=125units.



Q 4 :

The area of the quadrilateral ABCD with vertices A(2, 1, 1), B(1, 2, 5), C(−2, −3, 5) and D(1, −6, −7) is equal to      [2023]

  • 838

     

  • 48

     

  • 54

     

  • 938

     

(1)

The area of quadrilateral ABCD is equal to 12|AC×BD|.

Now, AC=(-2i^-3j^+5k^)-(2i^+j^+k^)=-4i^-4j^+4k^

and BD=(i^-6j^-7k^)-(i^+2j^+5k^)=-8j^-12k^

So, 12|AC×BD|=12||i^j^k^-4-440-8-12||

=12|80i^-48j^+32k^|=129728=838



Q 5 :

The distance of the point P(4, 6, −2) from the line passing through the point (−3, 2, 3) and parallel to a line with direction ratios 3, 3, −1 is equal to:        [2023]

  • 23

     

  • 14

     

  • 3

     

  • 6

     

(2)

Let Q=-3i^+2j^+3k^

PQ=-7i^-4j^+5k^, b=3i^+3j^-k^|b|=19

PQ×b=|i^j^k^-7-4533-1|=-11i^+8j^-9k^

Required distance=|PQ×b|b||=112+82+9219=14units



Q 6 :

Let the plane x+3y-2z+6=0 meet the coordinate axes at the points A, B, C. If the orthocenter of the triangle ABC is (α,β,67), then 98(α+β)2 is equal to _____ .   [2023]



(288)

Plane x+3y-2z+6=0 meets the coordinate axes at the points A, B, C.

For x-axis: x+0-0+6=0x=-6 i.e., (-6,0,0)

For y-axis: 0+3y-0+6=0y=-2 i.e., (0,-2,0)

For z-axis: 0+0-2z+6=0z=3 i.e., (0,0,3)

AB=6i^-2j^, BC=2j^+3k^, AC=6i^+3k^

Now, AP·BC=0

 (α+6,β,67)·(0,2,3)=0

2β+3·67=0β=-97

Similarly CP·AB=0

(α,β,-157)·(6,-2,0)=06α-2β=0

6α-2(-97)=06α=-187 α=-37

  98(α+β)2=98(-37-97)2=98(-127)2=98·14449=288



Q 7 :

Let the direction cosines of two lines satisfy the equations 4l+m-n=0 and 2mn+10nl+3lm=0. Then the cosine of the acute angle between these lines is:          [2026]

  • 1038

     

  • 20338

     

  • 10738

     

  • 10338

     

(4)

Direction cosines of two lines satisfy the equation

4+m-n=0    ...(1)

2mn+10n+3m=0    ...(2)

And we know

2+m2-n2=1    ...(3)

n=4+m  putting in eqn. (1)

n(2m+10)+3m=0

(4+m)(2m+10)+3m=0

8m+402+2m2+10m+3m=0

402+21m+2m2=0

(8+m)(5+2m)=0

Case 1: 8+m=0m=-8

Case 2: 5+2m=0m=-52

So direction ratio of L1 is ,-8,-4

and direction ratio of L2 is ,-52,32

cosθ=|2+202-622+642+1622+2524+924|

=152(9)382=10338

Ans. =10338



Q 8 :

Distance of the point (α,β,γ) from Y-axis is :

  • β

     

  • |β|

     

  • |β|+|γ|

     

  • α2+γ2

     

(4)

Ans.       α2+γ2

Explanation:

Required distance =(α-0)2+(β-β)2+(γ-0)2

                               =α2+γ2



Q 9 :

If the direction cosines of a line are k, k and k, then :

  • k>0

     

  • 0<k<1

     

  • k=1

     

  • k=13  or -13

     

(4)

Ans.           k=13 or  -13

Explanation:

Since, direction cosines of a line are k, k and k.

                 l=k, m=k and n=k

We know that,

                       l2+m2+n2=1

                k2+k2+k2=1

                                 k2=13

                                  k=±13



Q 10 :

Under what condition do (12,12,k) represent direction cosines of a line?

  • k=12

     

  • k=±12

     

  • k=-12

     

  • k can take any value

     

(2)

Ans.        k=±12

Explanation:

For (12,12,k) to represent direction cosines, we should have

             (12)2+(12)2+k2=1

or                        12+14+k2=1

                                              k2=1-34

                                        k=±12



Q 11 :

Any three numbers which are proportional to the direction cosines of a line, are called:

  • direction angles

     

  • direction ratios

     

  • another set of direction cosines

     

  • none of the above

     

(2)

Ans.         direction ratios

Explanation:

Any three numbers which are proportional to the direction cosines of a line, are called the direction ratios of the line. If l, m and n are direction cosines and a, b and c are direction ratios of a line, then a=λl, b=λm and c=λn for any non-zero λR.



Q 12 :

Direction ratios of two lines are a, b, c and 1bc, 1ca, 1ab. The lines are :

  • Mutually perpendicular

     

  • Parallel

     

  • Coincident

     

  • None of the above

     

(2)

Ans.        Parallel

Explanation:

As,         a(1/bc)=b(1/ca)=c(1/ab)

Hence, lines are parallel.



Q 13 :

Direction ratios of the line represented by the equation x=ay+b, z=cy+d are :

  • (a, 1, c)

     

  • (a, b-d, c)

     

  • (a, 1, a)

     

  • (b, ac, d)

     

(1)

Ans.       (a, 1, c)

Explanation:

Given,

                x=ay+b,    z=cy+d

         y=x-ba,    y=z-dc

        x-ba=y1=z-dc

Hence direction ratios are (a, 1, c).



Q 14 :

If α,β,γ are the angles that a line makes with the positive direction of X, Y, Z axes, respectively, then the direction cosines of the line are :

  • sinα, sinβ, sinγ

     

  • cosα, cosβ, cosγ

     

  • tanα, tanβ, tanγ

     

  • cos2α, cos2β, cos3γ

     

(2)

Ans.      cosα, cosβ, cosγ

Explanation:

Cosines of the angles α,β,γ made by a line with positive direction of X, Y, Z axes are cosα, cosβ, cosγ.



Q 15 :

The distance of a point P(a,b,c) from X-axis is :

  • a2+c2

     

  • a2+b2

     

  • b2+c2

     

  • b2+c2

     

(3)

Ans.       b2+c2

Explanation:

The required distance is the distance of P(a,b,c) from Q(a,0,0), which is b2+c2.



Q 16 :

A line makes equal angles with coordinate axis. Direction cosines of this line are :

  • ±(1,1,1)

     

  • ±(13,13,13)

     

  • ±(13,13,13)

     

  • ±(13,-13,-13)

     

(2)

Ans.     ±(13,13,13)

Explanation:

Let the line make angle α with each of the axis.

Then, its direction cosines are cosα, cosα, cosα.

Since

         cos2α+cos2α+cos2α=1

                                      3cos2α=1

                                        cos2α=13

                                   cosα=±13



Q 17 :

The vector equation of the symmetrical form of equation of straight line x-53=y+47=z-62 is:

  • r=(3i^+7j^+2k^)+μ(5i^+4j^-6k^)

     

  • r=(5i^+4j^-6k^)+μ(3i^+7j^+2k^)

     

  • r=(5i^-4j^-6k^)+μ(3i^-7j^-2k^)

     

  • r=(5i^-4j^+6k^)+μ(3i^+7j^+2k^)

     

(4)

Ans.      r=(5i^-4j^+6k^)+μ(3i^+7j^+2k^)

Explanation:

x-x1a=y-y1b=z-z1c have vector form

          r=(x1i^+y1j^+z1k^)+λ(ai^+bj^+ck^)

Required equation in vector form is

          r=(5i^-4j^+6k^)+μ(3i^+7j^+2k^)



Q 18 :

The lines in a space which are neither intersecting nor parallel, are called:

  • concurrent lines

     

  • intersecting lines

     

  • skew lines

     

  • parallel lines

     

(3)

Ans.        skew lines

Explanation:

In a space, there are lines which are neither intersecting nor parallel. Infact, such pair of lines are non-coplanar and are called skew-lines.



Q 19 :

The two lines x=ay+b, z=cy+d and x=a'y+b', z=c'y+d' will be perpendicular, if and only if:

  • aa'+cc'+1=0

     

  • aa'+bb'+cc'+1=0

     

  • aa'+bb'+cc'=0

     

  • (a+a')(b+b')+(c+c')=0

     

(1)

Ans.      aa'+cc'+1=0

Explanation:

                      x=ay+b

              y=x-ba

                      z=cy+d

              y=z-dc

             x-ba=y1=z-dc                     (i)

Similarly,  x-b'a'=y1=z-d'c'              (ii)

Lines are perpendicular so the sum of corresponding product of their dr's be zero. So for perpendicularity of lines, aa'+1+cc'=0.



Q 20 :

A line makes angles of 45° and 60° with the positive axis of X and Y respectively. The angle made by the same line with the positive axis of Z, is:

  • 30° or 60°

     

  • 60° or 90°

     

  • 90° or 120°

     

  • 60° or 120°

     

(4)

Ans.            60° or 120°

Explanation:

Given     α=45°,  β=60°,  γ=?

     cos2α+cos2β+cos2γ=1

                                     cos2γ=1-12-14=14

                                              γ=60° or 120°



Q 21 :

If α,β,γ be the angles which a line makes with the coordinate axis, then:

  • sin2α+cos2β+sin2γ=1

     

  • cos2α+cos2β+cos2γ=1

     

  • sin2α+sin2β+sin2γ=1

     

  • cos2α+cos2β+sin2γ=1

     

(2)

Ans.       cos2α+cos2β+cos2γ=1

Explanation:

If α,β,γ be the angles which a line makes with the coordinate axes, then cos2α+cos2β+cos2γ=1.



Q 22 :

The equation of a line passing through the point (-3,2,-4) and equally inclined to the axis, are:

  • x-3=y+2=z-4

     

  • x+31=y-21=z+41

     

  • x+31=y-22=z+43

     

  • None of the above

     

(2)

Ans.           x+31=y-21=z+41

Explanation:

Required equation of lines is

                   x+31=y-21=z+41



Q 23 :

The equation of straight line passing through the point (a,b,c) and parallel to Z-axis is:

  • x-a1=y-b1=z-c0

     

  • x-a0=y-b1=z-c1

     

  • x-a1=y-b0=z-c0

     

  • x-a0=y-b0=z-c1

     

(4)

Ans.        x-a0=y-b0=z-c1

Explanation:

The line through (a,b,c) is

               x-al=y-bm=z-cn            (i)

Since the line is parallel to Z-axis, therefore, the direction cosines are (0,0,1).

Hence, the line will be x-a0=y-b0=z-c1



Q 24 :

The length of the perpendicular from point (1,2,3) to the line x-63=y-72=z-7-2 is:

  • 5

     

  • 6

     

  • 7

     

  • 8

     

(3)

Ans.         7

Explanation:

Let a point on a given line be A(3λ+6, 2λ+7, -2λ+7).

Let the point B be (1,2,3).

   Direction ratios of AB =(3λ+6-1, 2λ+7-2, -2λ+7-3)

                                           =(3λ+5, 2λ+5, -2λ+4)

Given, direction ratios of the line are 3,2,-2.

    Lines are perpendicular.

  3(3λ+5)+2(2λ+5)-2(-2λ+4)=0

                9λ+15+4λ+10+4λ-8=0

                                                17λ+17=0

                                                               λ=-1

    Point A is (3,5,9).

  The length of perpendicular =(3-1)2+(5-2)2+(9-3)2

                                                    =4+9+36

                                                     =49

                                                     =7



Q 25 :

Equation of X-axis is:

  • x1=y1=z1

     

  • x0=y1=z1

     

  • x1=y0=z0

     

  • x0=y0=z1

     

(3)

Ans.          x1=y0=z0

Explanation:

Since, on X-axis coordinates of y and z are zero.

  Equation of X-axis becomes

       x-01-0=y-00-0=z-00-0

       x1=y0=z0



Q 26 :

The equations of X-axis in space are:

  • x=0, y=0

     

  • x=0, z=0

     

  • x=0

     

  • y=0, z=0

     

(4)

Ans.     y=0, z=0

Explanation:

On X-axis the y-coordinate and z-coordinate are zero.



Q 27 :

The lines x-21=y-31=4-zk and x-1k=y-42=z-5-2 are mutually perpendicular if the value of k is:

  • -23

     

  • 23

     

  • -2

     

  • 2

     

(1)

Ans.       -23

Explanation:

First line is,

               x-21=y-31=z-4-k

   Direction ratios of first line =1,1,-k

Second line is,

                   x-1k=y-42=z-5-2

   Direction ratios of second line =k,2,-2

We know, two lines are perpendicular to each other, if the dot product of their direction ratios is zero.

i.e.,    1×k+1×2+(-k)×(-2)=0

        k+2+2k=0

                      3k=-2

                        k=-23



Q 28 :

The shortest distance between the lines  x=y+2=6z-6 and x+1=2y=-12z is:

  • 12

     

  • 2

     

  • 1

     

  • 32

     

(2)

Ans.        2

Explanation:

The lines are      x6=y+26=z-11

and               x+112=y6=z-1

Here,               a1=-2j^+k^,    b1=6i^+6j^+k^,

                        a2=-i^,

                         b2=12i^+6j^-k^

                b1×b2=|i^j^k^661126-1|

                               =-12i^+18j^-36k^

Shortest distance=|(a2-a1)·(b1×b2)||b1×b2|

                                   =|(-i^+2j^-k^)·(-12i^+18j^-36k^)|(-12)2+(18)2+(-36)2

                                    =|12+36+36|1764=8442=2



Q 29 :

The distance of the plane r·(27i^+37j^-67k^)=1 from the origin is:

  • 1

     

  • 7

     

  • 17

     

  • None of these

     

(1)

Ans.       1

Explanation:

The distance of the plane  r·(27i^+37j^-67k^)=1 from the origin is 1.

[Since, r·n=d is the form of above equation, where d represents the distance of plane from the origin i.e., d=1]



Q 30 :

The locus represented by xy+yz=0 is:

  • a pair of perpendicular lines

     

  • a pair of parallel lines

     

  • a pair of parallel planes

     

  • a pair of perpendicular planes

     

(4)

Ans.      a pair of perpendicular planes

Explanation:

We have,              xy+yz=0

                                 xy=-yz

So, a pair of perpendicular planes.