Q 1 :

The correct stability order of carbocation is                         [2024]

  • (CH3)3C+>CH3-C+H2>(CH3)2C+H>C+H3

     

  • C+H3>(CH3)2C+H>CH3-C+H2>(CH3)3C+

     

  • (CH3)3C+>(CH3)2C+H>CH3-C+H2>C+H3

     

  • C+H3>CH3-C+H2>CH3-CHCH3|+>(CH3)3C+

     

(3)

Stability of carbocations follows the order: 3° > 2° > 1°. This is due to more hyperconjugation and +I stability in higher degree carbocations.

 



Q 2 :

A species having carbon with sextet of electrons and can act as electrophile is called                 [2024]

  • pentavalent carbon

     

  • carbon free radical

     

  • carbocation  

     

  • carbanion

     

(3)

Carbon can form maximum of four bond. There is nothing called pentavalent carbon.

 



Q 3 :

Correct order of stability of carbanion is                          [2024]

  • d > a > c > b

     

  • d > c > b > a

     

  • a > b > c > d

     

  • c > b > d > a

     

(2)

 



Q 4 :

The shape of carbocation is:                         [2024]

  • tetrahedral

     

  • trigonal planar

     

  • diagonal pyramidal

     

  • diagonal

     

(2)

 



Q 5 :

Number of carbocation from the following that are not stabilized by hyperconjugation is……….                 [2024]



(5)

For hyperconjugation to occur in carbocations, carbon carrying positive charge should be connected to an sp3 hybridized carbon and that sp3 hybridized carbon should have at least one H atom (called as αH).
Out of given seven structures, hyperconjugation is possible only in the following two structures:

 



Q 6 :

Which one of the carbocations from the following is most stable?                       [2025]

  •  

  •  

  •  

  •  

(3)

+M groups stabilize a carbocation by supplying electrons. Order of +M effect is: OCH3>OCOCH3>F

 



Q 7 :

The correct order of stability of following carbocations is:                      [2025]

  • C > A > B > D

     

  • B > C > A > D

     

  • C > B > A > D

     

  • A > B > C > D

     

(1)

 



Q 8 :

Which among the following halides will generate the most stable carbocation in the nucleophilic substitution reaction?            [2025]

  •  

  •  

  •  

  •  

(4)

Carbocation formed by (4) is stabilized by +M effect of three Ph groups hence is most stable in the given options. Stability order of carbocations is:

 



Q 9 :

The most stable carbocation from the following is:                         [2025]

  •  

  •  

  •  

  •  

(2)

Electron donating groups increase stability of a carbocation. –OMe group can donate electrons by +M effect from ortho and para position. +M effect of –OMe dominates over its –I effect. From meta position it withdraws electron density because of –I effect. Electron donation by +M effect of –OMe is more than the electron donation by hyperconjugation and +I effect of –CH3 group.

 



Q 10 :

The correct stability order of the following species/molecules is:                   [2025]

  • p>q>r

     

  • q>p>r

     

  • q>r>p

     

  • r>q>d

     

(3)

Cyclooctatetraene adopts non planar tub shaped structure to avoid anti aromaticity. So it is non aromatic. Thus stability order of given compounds is:

q (aromatic) > r (non aromatic) > p (anti aromatic)

 



Q 11 :

Consider the following compound (X)

The most stable and least stable carbon radicals, respectively, produced by homolytic cleavage of corresponding C–H bond are:          [2025]

  • II, IV

     

  • III, II

     

  • I, IV

     

  • II, I

     

(4)

Radical at II is stabilized by resonance, hyperconjugation and +I effect.

Radicals at III and IV are stabilized by hyperconjugation and +I effect.

There is no stabilizing effect for radical at I.



Q 12 :

In which pairs, the first ion is more stable than the second?                  [2025]

  • (B) and (D) only

     

  • (A) and (B) only

     

  • (B) and (C) only

     

  • (A) and (C) only

     

(2)

 



Q 13 :

Match the LIST-I with LIST-II                          [2025]

  List-I   List-II
A. Carbocation I. Species that can supply a pair of electrons
B. C-Free radical II. Species that can receive a pair of electrons.
C. Nucleophile III. sp2 hybridized carbon with empty p-orbital.
D. Electrophile IV. sp2/sp3 hybridized carbon with one unpaired electron.

 

Choose the correct answer from the options given below:

  • A-IV, B-II, C-III, D-I

     

  • A-II, B-III, C-I, D-IV

     

  • A-III, B-IV, C-II, D-I

     

  • A-III, B-IV, C-I, D-II

     

(4)

 



Q 14 :

Designate whether each of the following compounds is aromatic or not aromatic.              [2025]

  • e, g aromatic and a, b, c, d, f, h not aromatic

     

  • b, e, f, g aromatic and a, c, d, h not aromatic

     

  • a, b, c, d aromatic and e, f, g, h not aromatic

     

  • a, c, d, e, h aromatic and b, f, g not aromatic

     

(4)

 



Q 15 :

The most stable carbocation for the following is:                        [2023]

  • c

     

  • d

     

  • b

     

  • a

     

(1) 

Because +ve charge is delocalised with 2π-bonds and lone pair of 'N' atom in NH2 groups.



Q 16 :

The decreasing order of hydride affinity for following carbocations is:            [2023]

Choose the correct answer from the options given below:

  • A, C, D, B

     

  • A, C, B, D

     

  • C, A, D, B

     

  • C, A, B, D

     

(4)

Stability of carbocation 1Hydride affinity

D>B>A>CC>A>B>DStability of carbocationHydride affinity    



Q 17 :

Given below are two statements:

Statement I: ‘C–Cl’ bond is stronger in CH2 = CH–Cl than CH3CH2–Cl.

Statement II: The given optically active molecule,  on hydrolysis gives a solution that can rotate the plane polarized light.

In the light of the above statements, choose the correct answer from the options given below:                [2026]

  • Both Statement I and Statement II are false

     

  • Statement I is true but Statement II is false

     

  • Statement I is false but Statement II is true

     

  • Both Statement I and Statement II are true

     

(2)



Q 18 :

Arrange the following carbanions in the decreasing order of stability.

Choose the correct answer from the options given below:                   [2026]

  • IV > I > II > V > III

     

  • I > IV > II > V > III

     

  • IV > II > I > III > V

     

  • I > II > IV > V > III

     

(1)

Electron withdrawing groups increases stability of carbanion and electron donating groups decreases stability of carbanion.



Q 19 :

From the following, the least stable structure is:   [2026]

  •  

  •  

  •  

  •  

(4)

This resonating structure having +ve charge on adjacent atoms so it is least stable.



Q 20 :

The correct order of the rate of reaction of the following reactants with nucleophile by SN1 mechanism is:

(Given: Structures I and II are rigid)                               [2026]

  • IV < III < II < I

     

  • II < I < III < IV

     

  • I < II < III < IV

     

  • III < I < II < IV

     

(2)

Rate of SN1 Stability of C formed

(I) and (II) are unstable due to Bredt's rule, (I) has more +I effect.

(II)<(I)<(III)<(IV)



Q 21 :

Correct order of stability for the following is
CH2=CH-,  CH3-CH2-,  CHC-       [2026]

  • CHC>CH2=CH>CH3CH2

     

  • CHC->CH3-CH2->CH2=CH-

     

  • CH2=CH->CHC->CH3-CH2-

     

  • CH3CH2>CH2=CH>CHC

     

(1)

CH2=CH-CH3>CH2-CHC-

Stability %S

Order of stability

CHC->CH2=CH->CH3-CH2-