Oscillations NEET PYQ | Chapter-Wise Previous Year Questions

Q 1 :
If $x = 5 \sin (π t + \frac{π}{3})$ m represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are [2024]

5 cm, 2 s
5 m, 2 s
5 cm, 1 s
5 m, 1 s

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2

3

4

(2)

Given : $x = 5 \sin (π t + \frac{π}{3}) m$

Comparing the given equation with the standard equation of simple harmonic motion

$x = A \sin (ω t + ϕ)$

we get, A = 5 m and $ω = π$

Time period, $T = \frac{2 π}{ω} = \frac{2 π}{π} = 2$ $s$

Q 2 :
A simple pendulum oscillating in air has a period of $\sqrt{3}$ s. If it is completely immersed in non-viscous liquid, having density ${(\frac{1}{4})}^{th}$ of the material of the bob, the new period will be [2023]

$2 \sqrt{3}$ s
$\frac{2}{\sqrt{3}}$ s
$2$ s
$\frac{\sqrt{3}}{2}$ s

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4

(3)

For simple pendulum, $T = 2 π \sqrt{\frac{L}{g_{eff}}}$

According to the question, $g_{eff} = g (1 - \frac{ρ_{l}}{ρ_{0}}) = g (1 - \frac{1}{4}) = \frac{3}{4} g$

So, $\frac{T'}{T} = \frac{2 π \sqrt{\frac{L}{3 g / 4}}}{2 π \sqrt{\frac{L}{g}}} \Rightarrow T' = \frac{2}{\sqrt{3}}$

As, $T = \sqrt{3}$ $s$ so $T' = \frac{2}{\sqrt{3}} \times \sqrt{3} = 2 s$

Q 3 :
The displacement of a particle executing simple harmonic motion is given by, $y = A_{0} + A \sin ω t + B \cos ω t .$ Then the amplitude of its oscillation is given by [2019]

$A + B$
$A_{0} + \sqrt{A^{2} + B^{2}}$
$\sqrt{A^{2} + B^{2}}$
$\sqrt{A_{0}^{2} + {(A + B)}^{2}}$

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(3)

$y = A_{0} + A \sin ω t + B \cos ω t$

or $(y - A_{0}) = A \sin ω t + B \cos ω t$ or $y' = A \sin ω t + B \cos ω t$

$= A \cos (\frac{π}{2} - ω t) + B \cos ω t$

Amplitude $= \sqrt{A^{2} + B^{2} + 2 A B \cos \frac{π}{2}}$ $[∵ ϕ = \frac{π}{2}]$

$= \sqrt{A^{2} + B^{2}}$

Q 4 :
The distance covered by a particle undergoing SHM in one time period is (amplitude = A) [2019]

zero
A
2A
4A

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2

3

4

Topic Question Set

Q 1 :
If $x = 5 \sin (π t + \frac{π}{3})$ m represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are [2024]

Q 2 :
A simple pendulum oscillating in air has a period of $\sqrt{3}$ s. If it is completely immersed in non-viscous liquid, having density ${(\frac{1}{4})}^{th}$ of the material of the bob, the new period will be [2023]

Q 3 :
The displacement of a particle executing simple harmonic motion is given by, $y = A_{0} + A \sin ω t + B \cos ω t .$ Then the amplitude of its oscillation is given by [2019]

Q 4 :
The distance covered by a particle undergoing SHM in one time period is (amplitude = A) [2019]

(4)

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Topic Question Set

Q 1 : If x=5sin(πt+π3) m represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are [2024]

Q 2 : A simple pendulum oscillating in air has a period of 3 s. If it is completely immersed in non-viscous liquid, having density (14)th of the material of the bob, the new period will be [2023]

Q 3 : The displacement of a particle executing simple harmonic motion is given by, y=A0+Asinωt+Bcosωt. Then the amplitude of its oscillation is given by [2019]

Q 4 : The distance covered by a particle undergoing SHM in one time period is (amplitude = A) [2019]

(4)

Want Us to Email you About Special Offers & Updates?

Q 1 :
If $x = 5 \sin (π t + \frac{π}{3})$ m represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are [2024]

Q 2 :
A simple pendulum oscillating in air has a period of $\sqrt{3}$ s. If it is completely immersed in non-viscous liquid, having density ${(\frac{1}{4})}^{th}$ of the material of the bob, the new period will be [2023]

Q 3 :
The displacement of a particle executing simple harmonic motion is given by, $y = A_{0} + A \sin ω t + B \cos ω t .$ Then the amplitude of its oscillation is given by [2019]

Q 4 :
The distance covered by a particle undergoing SHM in one time period is (amplitude = A) [2019]