Oscillation and Simple Harmonic Motion | Physics JEE previous year questions with Solutions

(1)

Applied simple harmonic motions on the particle,

$x_{1} = \sqrt{7} \sin 5 t and x_{2} = 2 \sqrt{7} \sin (5 t + \frac{π}{3})$

From phasor,

Amplitude of resultant SHM,

$A = \sqrt{{(\sqrt{7})}^{2} + {(2 \sqrt{7})}^{2} + 2 \times 2 \times 7 \cos (\frac{π}{3})} = 7 cm$

The maximum acceleration of the particle

$a_{\max} = ω^{2} A = 25 \times 7 = 175 {cms}^{- 2} = 175 \times 10^{- 2} {ms}^{- 2}$

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