Q 1 :    

A simple pendulum doing small oscillations at a place R height above earth surface has time period of T1=4s. T2 would be it's time period if it is brought to a point which is at a height 2R from earth surface.

Choose the correct relation [R = radius of earth]                    [2024]         

  • 2T1=3T2

     

  • 2T1=T2

     

  • T1=T2

     

  • 3T1=2T2

     

(D)    T=2πlg=2πlr2GM=2πlGMr

           T2T1=r2r1=3R2R2T2=3T1

 



Q 2 :    

A mass m is suspended from a spring of negligible mass and the system oscillates with a frequency f1. The frequency of oscillations if a mass 9 m is suspended from the same spring is f2. The value of f1f2 is _______ .           [2024]



(3)

 



Q 3 :    

In simple harmonic motion, the total mechanical energy of a given system is E. If the mass of oscillating particle P is doubled, then the new energy of the system for same amplitude is                   [2024]

[IMAGE 121]

  • E2

     

  • E

     

  • 2E

     

  • E/2

     

(2)

Total energy E=KE+PE

E=12mω2(A2-x2)+12mω2x2

E=12kA2, since A is same, T.E. will be same



Q 4 :    

The time period of simple harmonic motion of mass M in the given figure is παM5k, where the value of α is ________ .              [2024]

[IMAGE 122]



(12)

keq=2k·k3k+k=5k3

Angular frequency of oscillation (ω)=keqm

(ω)=5k3m

Period of oscillation (τ)=2πω=2π3m5k

=π12m5k