Q 1 :    

Given below are two statements:

Statement (I): Aminobenzene and aniline are same organic compounds.

Statement (II): Aminobenzene and aniline are different organic compounds.

In the light of the above statements, choose the most appropriate answer from the options given below:             [2024]

  • Both Statement I and Statement II are correct

     

  • Statement I is correct but Statement II is incorrect

     

  • Statement I is incorrect but Statement II is correct

     

  • Both Statement I and Statement II are incorrect

     

(2)

Aniline is IUPAC accepted name of aminobenzene.

 



Q 2 :    

X g of ethylamine is subjected to reaction with NaNO2/HCl followed by water; evolved dinitrogen gas which occupied 2.24 L volume at STP. X is ______ ×10-1 g.                 [2024]



(45)

C2H5NH2NaNO2+HClC2H5N2+

                    H2OC2H5OH+N2

Moles of nitrogen

(nN2)=Volume at STP in L22.4=2.2422.4mol=0.1mol

From reaction it is clear that moles of ethylamine (nC2H5NH2)=nN2=0.1mol.

Mass of ethylamine = nC2H5NH2× molar mass of ethylamine

=0.1mol×45g mol-1=45×10-1g



Q 3 :    

X g of ethanamine was subjected to reaction with NaNO2/HCl followed by hydrolysis to liberate N2 and HCl. The HCl generated was completely neutralised by 0.2 moles of NaOH. X is ______ g.               [2024]



(9)

   HCl+NaOHNaCl+H2O

   By stoichiometry

   nHCl=nNaOH=0.2mol

   C2H5NH2NaNO2+HCl

   C2H5N2+Cl-H2OC2H5OH+N2+HCl

   nC2H5NH2=nHCl=0.2mol

   WC2H5NH2(X)=MC2H5NH2×nC2H5NH2=45×0.2g=9g

 



Q 4 :    

Identify B formed in the reaction.                                           [2024]

Cl-(CH2)4-Clexcess NH3ANaOHB+H2O+NaCl

  •  

  • H2N-(CH2)4-NH2

     

  • ClN+H3-(CH2)4-N+H3Cl-

     

  •  

(2)

In Hoffmann ammonolysis reaction excess of NH3 forms primary amine. Since NH3 is in excess, it replaced both Cl of substrate.

 



Q 5 :    

Find out the major product formed from the following reaction. [Me:-CH3]                               [2024]

  •  

  •  

  •  

  •  

(3)



Q 6 :    

Phthalimide is made to undergo the following sequence of reactions.                                                     [2024]

Phthalimide(i) KOH(ii) BenzylchlorideP

Total number of π bonds present in product 'P' is/are ______



(8)

 



Q 7 :    

An amine (X) is prepared by ammonolysis of benzyl chloride. On adding p-toluenesulphonyl chloride to it, the solution remains clear. The molar mass of the amine (X) formed is ______ g mol-1.

(Given molar mass in g mol-1: C : 12, H : 1, O : 16, N : 14)                                [2024]



(287)

Ammonolysis of alkyl halides produces a mixture of primary, secondary and tertiary amines and quaternary ammonium salt. Major product formed depends upon relative amount of alkyl halide and ammonia.

As on adding p-toluenesulphonyl chloride (Hinsberg reagent) solution remains clear, this means the amine X is tertiary amine. Formula of X is (C6H5CH2)3N.
Molar mass of

X=[3×(7×12+7×1)+14]g mol-1=287g mol-1