Q.

X g of ethanamine was subjected to reaction with NaNO2/HCl followed by hydrolysis to liberate N2 and HCl. The HCl generated was completely neutralised by 0.2 moles of NaOH. X is ______ g.               [2024]


Ans.

(9)

   HCl+NaOHNaCl+H2O

   By stoichiometry

   nHCl=nNaOH=0.2mol

   C2H5NH2NaNO2+HCl

   C2H5N2+Cl-H2OC2H5OH+N2+HCl

   nC2H5NH2=nHCl=0.2mol

   WC2H5NH2(X)=MC2H5NH2×nC2H5NH2=45×0.2g=9g