X g of ethylamine is subjected to reaction with followed by water; evolved dinitrogen gas which occupied 2.24 L volume at STP. X is ______ g.

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
X g of ethylamine is subjected to reaction with ${NaNO}_{2} / HCl$ followed by water; evolved dinitrogen gas which occupied 2.24 L volume at STP. X is ______ $\times 10^{- 1}$ g. [2024]

Ans.
(45)

$C_{2} H_{5} {NH}_{2} \overset{{NaNO}_{2} + HCl}{\to} C_{2} H_{5} N_{2}^{+}$

$\overset{H_{2} O}{\to} C_{2} H_{5} OH + N_{2}$

Moles of nitrogen

$(n_{N_{2}}) = \frac{Volume at STP in L}{22.4} = \frac{2.24}{22.4} mol = 0.1 mol$

From reaction it is clear that moles of ethylamine $(n_{C_{2} H_{5} {NH}_{2}}) = n_{N_{2}} = 0.1 mol .$

Mass of ethylamine = $n_{C_{2} H_{5} {NH}_{2}} \times$ molar mass of ethylamine

$= 0.1 mol \times 45 {g mol}^{- 1} = 45 \times 10^{- 1} g$

Want Us to Email you About Special Offers & Updates?