Q 1 :

One end of a horizontal thick copper wire of length 2L and radius 2R is welded to an end of another horizontal thin copper wire of length L and radius R. When the arrangement is stretched by applying forces at two ends, the ratio of the elongation in the thin wire to that in the thick wire is                      [2013]

  • 0.25

     

  • 0.50

     

  • 2.00

     

  • 4.00

     

(3)

Using, Y=F/AΔ/0

Y=F/π(2R)2Δ1/2L=F/πR2Δ2/L

 Δ2Δ1=2



Q 2 :

The adjacent graph shows the extension (Δ) of a wire of length 1 m suspended from the top of a roof at one end and with a load W connected to the other end. If the cross-sectional area of the wire is 10-6m2, calculate the Young's modulus of the material of the wire.                    [2003]

[IMAGE 373]

  • 2×1011 N/m

     

  • 2×10-11 N/m

     

  • 3×10-12 N/m

     

  • 2×10-13 N/m

     

(1)

Using,  Y=F/AΔ/=FA·Δ=20×110-6×10-4

=2×1011 N/m2



Q 3 :

A block of weight 100 N is suspended by copper and steel wires of same cross sectional area 0.5 cm2 and, length m and 1 m, respectively. Their other ends are fixed on a ceiling as shown in figure. The angles subtended by copper and steel wires with ceiling are 30° and 60°, respectively. If elongation in copper wire is (Δlc) and elongation in steel wire is (Δls), then the ratio ΔlcΔls is _______.

[Young's modulus for copper and steel are 1×1011 N/m2 and 2×1011N/m2, respectively.]                    [2019]

[IMAGE 374]



(2)

[IMAGE 375]

Given : lc=3 m,  ls=1 m,  Yc=1×1011 N/m2 and Ys=2×1011 N/m2

At equilibrium, Tscos60°=Tccos30°

Ts2=Tc32

Ts=3TcTcTs=13

 lcls=31

and    YcYs=1×10112×1011=12

From, Y=FlAΔlΔl=FlAY

Here, As=Ac

 ΔlcΔls=(TcTs)×(lcls)×(YsYc)=(13)×(31)×(21)=2



Q 4 :

In plotting stress versus strain curves for two materials P and Q, a student by mistake puts strain on the y-axis and stress on the x-axis as shown in the figure. Then the correct statement(s) is (are)                       [2015]

[IMAGE 376]

  • P has more tensile strength than Q

     

  • P is more ductile than Q

     

  • P is more brittle than Q

     

  • The Young's modulus of P is more than that of Q

     

Select one or more options

(1, 2)

 From graph, the maximum stress that P can withstand before breaking is greater than Q.

[IMAGE 377]

The strain of P is more than Q therefore P is more ductile.

  Y=stressstrain  So for a given strain, stress is more for Q.

  YQ>YP