The adjacent graph shows the extension of a wire of length 1 m suspended from the top of a roof at one end and with a load W connected to the other end. If the cross-sectional area of the wire is , calculate the Young's modulus of the material of the wir

Question

The adjacent graph shows the extension $(Δ ℓ)$ of a wire of length 1 m suspended from the top of a roof at one end and with a load W connected to the other end. If the cross-sectional area of the wire is $10^{- 6} m^{2}$ , calculate the Young's modulus of the material of the wire. [2003]

Smart Achievers · Accepted Answer

(1)

$Using, Y = \frac{F / A}{Δ ℓ / ℓ} = \frac{F}{A} \cdot \frac{ℓ}{Δ ℓ} = \frac{20 \times 1}{10^{- 6} \times 10^{- 4}}$

$= 2 \times 10^{11} {N/m}^{2}$

Solution

Q.
The adjacent graph shows the extension $(Δ ℓ)$ of a wire of length 1 m suspended from the top of a roof at one end and with a load W connected to the other end. If the cross-sectional area of the wire is $10^{- 6} m^{2}$ , calculate the Young's modulus of the material of the wire. [2003]

1 $2 \times 10^{11} N/m$

2 $2 \times 10^{- 11} N/m$

3 $3 \times 10^{- 12} N/m$

4 $2 \times 10^{- 13} N/m$

Ans.
(1)

$Using, Y = \frac{F / A}{Δ ℓ / ℓ} = \frac{F}{A} \cdot \frac{ℓ}{Δ ℓ} = \frac{20 \times 1}{10^{- 6} \times 10^{- 4}}$

$= 2 \times 10^{11} {N/m}^{2}$

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Solution

Q. The adjacent graph shows the extension (Δℓ) of a wire of length 1 m suspended from the top of a roof at one end and with a load W connected to the other end. If the cross-sectional area of the wire is 10-6 m2, calculate the Young's modulus of the material of the wire. [2003]

1 2×1011 N/m

2 2×10-11 N/m

3 3×10-12 N/m

4 2×10-13 N/m

Ans. (1) Using, Y=F/AΔℓ/ℓ=FA·ℓΔℓ=20×110-6×10-4 =2×1011 N/m2