Q 11 :

A 10μC charge is divided into two parts and placed at 1 cm distance so that the repulsive force between them is maximum. The charges of the two parts are       [2023]

  • 9μC, 1μC

     

  • 5μC, 5μC

     

  • 7μC, 3μC

     

  • 8μC, 2μC

     

(2)

Divide q=10μC into two parts x and q-x.

F=Kx(q-x)r2

For F to be maximum

dFdx=Kr2(q-2x)=0x=q2



Q 12 :

A point charge q1=4q0 is placed at the origin. Another point charge q2=-q0 is placed at x=12 cm. The charge of a proton is q0. The proton is placed on the x-axis so that the electrostatic force on the proton is zero. In this situation, the position of the proton from the origin is ________ cm.              [2023]



(24)

[IMAGE 125]

q0x2=4q0(x+12)2

x+12=2xx=12

Distance from origin=x+12=24 cm



Q 13 :

Three point charges q, -2q and 2q are placed on the x-axis at distances x=0, x=34R and x=R respectively from the origin, as shown. If q=2×10-6 C and R=2 cm, the magnitude of the net force experienced by the charge -2q is _______ N.                    [2023]

[IMAGE 126]



(5440)

[IMAGE 127]

FBA=Kq(2q)(34R)2=32Kq29R2

FBC=K(2q)(2q)(R4)2=64Kq2R2

FB=FBC-FBA=544Kq29R2

=544×9×109×(2×10-6)29×(2×10-2)2=5440 N