Alternating Current | Physics JEE Main questions with Solutions

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$In DC circuit:$

$I = \frac{V}{R} (at steady state)$

$R = \frac{20}{5} = 4 Ω$

$In AC circuit:$

$I = \frac{V}{Z} \Rightarrow 4 = \frac{20}{\sqrt{R^{2} + {(L ω)}^{2}}}$

$16 + {(L ω)}^{2} = 25 \Rightarrow L ω = 3$

$L = \frac{3}{2 \times π \times f} = \frac{3}{2 \times 3 \times 50} = \frac{1}{100} = 10 mH$

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