Q.

A series LCR circuit is connected to an alternating source of emf E. The current amplitude at resonant frequency is I0. If the value of resistance R becomes twice of its initial value then amplitude of current at resonance will be          [2025]

1 I0  
2 I02  
3 I02  
4 2I0  

Ans.

(2)

At resonance Z = R

Initially, I0=ER

Finally, I'=E2R=I02