( x + 1 x ) 2 ? d x equals:

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Other Competitive Exams

NDA

NDA

MATHS

Courses

Class Room Courses
Online Live Courses
Online Recorded Courses

ONLINE COURSES

More

Solution

Q.
$\int {(x + \frac{1}{x})}^{2} d x$ equals:

1 $\frac{x^{3}}{3} + \frac{1}{x} - 2 x + c$

2 $\frac{x^{3}}{3} - \frac{1}{x} + 2 x + c$

3 $\frac{x^{3}}{3} - \frac{1}{x} - 2 x + c$

4 $\frac{x^{3}}{3} + \frac{1}{x} + 2 x + c$

Ans.
(2)

Ans. $\frac{x^{3}}{3} - \frac{1}{x} + 2 x + c$

Explanation :

$Let$ $I = \int {(x + \frac{1}{x})}^{2} d x$

$= \int (x^{2} + \frac{1}{x^{2}} + 2) d x$

$= \int x^{2} d x + \int \frac{1}{x^{2}} d x + \int 2 d x$

$= \frac{x^{3}}{3} - \frac{1}{x} + 2 x + c$

Want Us to Email you About Special Offers & Updates?