∫x(xtan-1x+(lnx)(ln(lnx)))+tan-1x(x3+x)lnx=f(x)+c where 'c' is integration constant & f(e)=0
Then [limx→1+f(x)tan(πx2)+1110]=_____, where [.] denotes GIF
(2)
Given ∫tan-1x·1x(lnx)+11+x2·ln(lnx)
∴ f(x)=(tan-1x)ln(lnx)