Width of one of the two slits in Young's double slit interference experiment is half of the other slit. The ratio of the maximum to the minimum intensity in the interference pattern is: [2025]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

Q.
Width of one of the two slits in a Young's double slit interference experiment is half of the other slit. The ratio of the maximum to the minimum intensity in the interference pattern is: [2025]

1 $(2 \sqrt{2} + 1) : (2 \sqrt{2} - 1)$

2 $(3 + 2 \sqrt{2}) : (3 - 2 \sqrt{2})$

3 9 : 1

4 3 : 1

Ans.
(2)

$I \propto width$ $I_{\max} = {(\sqrt{I_{1}} + \sqrt{I_{2}})}^{2}$

$∴ I_{1} = I_{0}, I_{2} = 2 I_{0}$ $I_{\min} = {(\sqrt{I_{1}} - \sqrt{I_{2}})}^{2}$

$\frac{I_{\max}}{I_{\min}} = \frac{{(\sqrt{2} + 1)}^{2}}{{(\sqrt{2} - 1)}^{2}} \Rightarrow \frac{3 + 2 \sqrt{2}}{3 - 2 \sqrt{2}}$

Solution

Q.
Width of one of the two slits in a Young's double slit interference experiment is half of the other slit. The ratio of the maximum to the minimum intensity in the interference pattern is: [2025]

1 $(2 \sqrt{2} + 1) : (2 \sqrt{2} - 1)$

2 $(3 + 2 \sqrt{2}) : (3 - 2 \sqrt{2})$

3 9 : 1

4 3 : 1

Ans.
(2)

$I \propto width$ $I_{\max} = {(\sqrt{I_{1}} + \sqrt{I_{2}})}^{2}$

$∴ I_{1} = I_{0}, I_{2} = 2 I_{0}$ $I_{\min} = {(\sqrt{I_{1}} - \sqrt{I_{2}})}^{2}$

$\frac{I_{\max}}{I_{\min}} = \frac{{(\sqrt{2} + 1)}^{2}}{{(\sqrt{2} - 1)}^{2}} \Rightarrow \frac{3 + 2 \sqrt{2}}{3 - 2 \sqrt{2}}$

Want Us to Email you About Special Offers & Updates?

Solution

Q. Width of one of the two slits in a Young's double slit interference experiment is half of the other slit. The ratio of the maximum to the minimum intensity in the interference pattern is: [2025]

1 (22+1) : (22–1)

2 (3+22) : (3–22)

3 9 : 1

4 3 : 1

Ans. (2) I∝width Imax=(I1+I2)2 ∴ I1=I0, I2=2I0 Imin=(I1–I2)2 ImaxImin=(2+1)2(2–1)2 ⇒ 3+223–22

Want Us to Email you About Special Offers & Updates?

Q.
Width of one of the two slits in a Young's double slit interference experiment is half of the other slit. The ratio of the maximum to the minimum intensity in the interference pattern is: [2025]

1 $(2 \sqrt{2} + 1) : (2 \sqrt{2} - 1)$

2 $(3 + 2 \sqrt{2}) : (3 - 2 \sqrt{2})$

Ans.
(2)

$I \propto width$ $I_{\max} = {(\sqrt{I_{1}} + \sqrt{I_{2}})}^{2}$

$∴ I_{1} = I_{0}, I_{2} = 2 I_{0}$ $I_{\min} = {(\sqrt{I_{1}} - \sqrt{I_{2}})}^{2}$

$\frac{I_{\max}}{I_{\min}} = \frac{{(\sqrt{2} + 1)}^{2}}{{(\sqrt{2} - 1)}^{2}} \Rightarrow \frac{3 + 2 \sqrt{2}}{3 - 2 \sqrt{2}}$