A monochromatic light of frequency Hz travelling through air, is incident on a medium of refractive index '2'. Wavelength of the refracted light will be: [2025]

Question

A monochromatic light of frequency $5 \times 10^{14}$ Hz travelling through air, is incident on a medium of refractive index '2'. Wavelength of the refracted light will be: [2025]

Smart Achievers · Accepted Answer

(1)

Wave speed, $v = f λ$

As $μ$ = 2 therefore; speed $c \to \frac{c}{2}$

$λ_{medium} = \frac{c}{2 f} = \frac{3 \times 10^{8}}{2 \times 5 \times 10^{14}} = 3 \times 10^{- 7} m$

$= 3 \times 10^{- 7} \times 10^{9} nm = 300 nm$

Solution

Q.
A monochromatic light of frequency $5 \times 10^{14}$ Hz travelling through air, is incident on a medium of refractive index '2'. Wavelength of the refracted light will be: [2025]

1 300 nm

2 600 nm

3 400 nm

4 500 nm

Ans.
(1)

Wave speed, $v = f λ$

As $μ$ = 2 therefore; speed $c \to \frac{c}{2}$

$λ_{medium} = \frac{c}{2 f} = \frac{3 \times 10^{8}}{2 \times 5 \times 10^{14}} = 3 \times 10^{- 7} m$

$= 3 \times 10^{- 7} \times 10^{9} nm = 300 nm$

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