Which of the following nuclear fragments corresponding to nuclear fission between neutron and uranium isotope is correct?

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Q.
Which of the following nuclear fragments corresponding to nuclear fission between neutron $({}_{0}^{1}n)$ and uranium isotope $({}_{92}^{235}U)$ is correct [2024]

1 ${}_{56}^{144}B a + {}_{36}^{89}K r + 3 {}_{0}^{1}n$

2 ${}_{56}^{144}B a + {}_{36}^{89}K r + 4 {}_{0}^{1}n$

3 ${}_{51}^{153}S b + {}_{41}^{99}N b + 3 {}_{0}^{1}n$

4 ${}_{56}^{140}X e + {}_{38}^{94}S r + 3 {}_{0}^{1}n$

Ans.
(1)

After balancing mass number and atomic number,the original fission reaction is given by,

${}_{92}^{235}U + {}_{0}^{1}n \to {}_{56}^{144}B a + {}_{36}^{89}K r + 3 {}_{0}^{1}n$

Solution

Q.
Which of the following nuclear fragments corresponding to nuclear fission between neutron $({}_{0}^{1}n)$ and uranium isotope $({}_{92}^{235}U)$ is correct [2024]

1 ${}_{56}^{144}B a + {}_{36}^{89}K r + 3 {}_{0}^{1}n$

2 ${}_{56}^{144}B a + {}_{36}^{89}K r + 4 {}_{0}^{1}n$

3 ${}_{51}^{153}S b + {}_{41}^{99}N b + 3 {}_{0}^{1}n$

4 ${}_{56}^{140}X e + {}_{38}^{94}S r + 3 {}_{0}^{1}n$

Ans.
(1)

After balancing mass number and atomic number,the original fission reaction is given by,

${}_{92}^{235}U + {}_{0}^{1}n \to {}_{56}^{144}B a + {}_{36}^{89}K r + 3 {}_{0}^{1}n$

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Solution

Q. Which of the following nuclear fragments corresponding to nuclear fission between neutron (n01) and uranium isotope (U92235) is correct [2024]

1 B56144a+K3689r+3n01

2 B56144a+K3689r+4n01

3 S51153b+N4199b+3n01

4 X56140e+S3894r+3n01

Ans. (1) After balancing mass number and atomic number,the original fission reaction is given by, U92235+n01→B56144a+K3689r+3n01

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Q.
Which of the following nuclear fragments corresponding to nuclear fission between neutron $({}_{0}^{1}n)$ and uranium isotope $({}_{92}^{235}U)$ is correct [2024]

1 ${}_{56}^{144}B a + {}_{36}^{89}K r + 3 {}_{0}^{1}n$

2 ${}_{56}^{144}B a + {}_{36}^{89}K r + 4 {}_{0}^{1}n$

3 ${}_{51}^{153}S b + {}_{41}^{99}N b + 3 {}_{0}^{1}n$

4 ${}_{56}^{140}X e + {}_{38}^{94}S r + 3 {}_{0}^{1}n$

Ans.
(1)

After balancing mass number and atomic number,the original fission reaction is given by,

${}_{92}^{235}U + {}_{0}^{1}n \to {}_{56}^{144}B a + {}_{36}^{89}K r + 3 {}_{0}^{1}n$