In a hypothetical fission reaction, The identity of emitted particles (R) is

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Solution

Q.
In a hypothetical fission reaction

${}_{92}{X^{236}} \to {}_{56}{Y^{141}} + {}_{36}{Z^{92}} + 3 R$

The identity of emitted particles (R) is [2024]

1 $γ - r a d i a t i o n s$

2 $E l e c t r o n$

3 $N e u t r o n$

4 $P r o t o n$

Ans.
(3)

Z in LHS = 92

Z in RHS = 56 + 36 = 92

A in LHS = 236

A in RHS = 141 + 92 = 233

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