Q.

Which figure shows the correct variation of applied potential difference (V) with photoelectric current (i) at two different intensities of light (I1<I2) of same wavelengths  [2024]

 

 

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Ans.

(1)

Saturation current depends on intensity of incident light.
Also, according to question, both have same wavelength.
Hence stopping potential will remain same, it means KEmax will be same.
Since I2>I1, hence saturation current corresponding to I2 will be greater than that corresponding to I1.