In photoelectric effect an em-wave is incident on a metal surface and electrons are ejected from the surface. If the work function of the metal is 2.14 eV and stoppin potential is 2 V, what is the wavelength of the em-wave? (Given hc = 1242 eVm where h i

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Solution

Q.
In photoelectric effect an em-wave is incident on a metal surface and electrons are ejected from the surface. If the work function of the metal is 2.14 eV and stopping potential is 2 V, what is the wavelength of the em-wave

(Given hc = 1242 eVm where h is the Planck's constant and c is the speed of light in vacuum.) [2025]

1 400 nm

2 600 nm

3 200 nm

4 300 nm

Ans.
(4)

Using photoelectric equation ${eV}_{s} = E$

2 eV = E – 2.14 eV $\Rightarrow$ E = 4.14 eV

$E = \frac{h c}{λ} \Rightarrow λ = \frac{1242}{4.14} = 300 nm$

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