Two spherical bodies of masses and and radii and respectively, are released in free space with initial

Question

Two spherical bodies of masses $m$ and $5 m$ and radii $R$ and $2 R$ respectively, are released in free space with initial separation between their centres equal to $12 R$ . If they attract each other due to gravitational force only, the distance covered by smaller sphere just before collision is

Smart Achievers · Accepted Answer

(1)

$Distance covered by the smaller sphere = 10 R - \frac{5 R}{2} = \frac{15 R}{2}$

Solution

Q.
Two spherical bodies of masses $m$ and $5 m$ and radii $R$ and $2 R$ respectively, are released in free space with initial separation between their centres equal to $12 R$ . If they attract each other due to gravitational force only, the distance covered by smaller sphere just before collision is

1 $\frac{15 R}{2}$

2 $\frac{13 R}{2}$

3 $10 R$

4 $\frac{17 R}{2}$

Ans.
(1)

$Distance covered by the smaller sphere = 10 R - \frac{5 R}{2} = \frac{15 R}{2}$

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Solution

Q. Two spherical bodies of masses m and 5m and radii R and 2R respectively, are released in free space with initial separation between their centres equal to 12R. If they attract each other due to gravitational force only, the distance covered by smaller sphere just before collision is

1 15R2

2 13R2

3 10R

4 17R2