Two particles of mass M and 5M are released in free space with initial separation distance d between them

Question

Two particles of mass M and 5M are released in free space with initial separation distance d between them. If they attract each other due to gravitational force only, then the ratio of distances covered by small mass to higher mass just before collision is

Smart Achievers · Accepted Answer

(4)

Total distance moved by the bodies,

$x_{1} + x_{2} = 12 R - 3 R = 9 R$ $. . . . . . . . . . . . . (i)$

Also, $M x_{1} = 5 M x_{2}$ $. . . . . . . . . . . . . . . . . . . . . . . (i i)$

After solving above equations, we get

$x_{1} = 7.5 R$

$x_{2} = 1.5 R$

Solution

Q.
Two particles of mass M and 5M are released in free space with initial separation distance d between them. If they attract each other due to gravitational force only, then the ratio of distances covered by small mass to higher mass just before collision is

1 6

2 4

3 3

4 5

Ans.
(4)

Total distance moved by the bodies,

$x_{1} + x_{2} = 12 R - 3 R = 9 R$ $. . . . . . . . . . . . . (i)$

Also, $M x_{1} = 5 M x_{2}$ $. . . . . . . . . . . . . . . . . . . . . . . (i i)$

After solving above equations, we get

$x_{1} = 7.5 R$

$x_{2} = 1.5 R$

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Solution

Q. Two particles of mass M and 5M are released in free space with initial separation distance d between them. If they attract each other due to gravitational force only, then the ratio of distances covered by small mass to higher mass just before collision is

1 6

2 4

3 3

4 5

Ans. (4) Total distance moved by the bodies, x1+x2=12R-3R=9R .............(i) Also, Mx1=5Mx2 .......................(ii) After solving above equations, we get x1=7.5R x2=1.5R

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Q.
Two particles of mass M and 5M are released in free space with initial separation distance d between them. If they attract each other due to gravitational force only, then the ratio of distances covered by small mass to higher mass just before collision is

Ans.
(4)

Total distance moved by the bodies,

$x_{1} + x_{2} = 12 R - 3 R = 9 R$ $. . . . . . . . . . . . . (i)$

Also, $M x_{1} = 5 M x_{2}$ $. . . . . . . . . . . . . . . . . . . . . . . (i i)$

After solving above equations, we get

$x_{1} = 7.5 R$

$x_{2} = 1.5 R$