Two cards are drawn at random from a pack of 52 playing cards. If the odds against of the event that one card is heart and other is an ace are n:1, then n=

Question

Two cards are drawn at random from a pack of 52 playing cards. If the odds against of the event that one card is heart and other is an ace are $n : 1$ , then $n =$

Smart Achievers · Accepted Answer

(25)

$Heart and Not Ace = 12$

$Ace and Not Heart = 3$

$Ace and Heart = 1$

$P (E) = \frac{{}^{12}C_{1} . {}^{3}C_{1} + {}^{3}C_{1} . {}^{1}C_{1} + {}^{12}C_{1} . {}^{1}C_{1}}{{}^{52}C_{2}} = \frac{1}{26}$

Solution

Q.
Two cards are drawn at random from a pack of 52 playing cards. If the odds against of the event that one card is heart and other is an ace are $n : 1$ , then $n =$

Ans.
(25)

$Heart and Not Ace = 12$

$Ace and Not Heart = 3$

$Ace and Heart = 1$

$P (E) = \frac{{}^{12}C_{1} . {}^{3}C_{1} + {}^{3}C_{1} . {}^{1}C_{1} + {}^{12}C_{1} . {}^{1}C_{1}}{{}^{52}C_{2}} = \frac{1}{26}$

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Solution

Q. Two cards are drawn at random from a pack of 52 playing cards. If the odds against of the event that one card is heart and other is an ace are n:1, then n=

Ans. (25) Heart and Not Ace=12 Ace and Not Heart=3 Ace and Heart=1 P(E)=C112.C13+C13.C11+C112.C11C252=126

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Q.
Two cards are drawn at random from a pack of 52 playing cards. If the odds against of the event that one card is heart and other is an ace are $n : 1$ , then $n =$

Ans.
(25)

$Heart and Not Ace = 12$

$Ace and Not Heart = 3$

$Ace and Heart = 1$

$P (E) = \frac{{}^{12}C_{1} . {}^{3}C_{1} + {}^{3}C_{1} . {}^{1}C_{1} + {}^{12}C_{1} . {}^{1}C_{1}}{{}^{52}C_{2}} = \frac{1}{26}$