A bag contains 3 white, 4 black and 2 red balls. If 2 balls are drawn at random (without replacement), then the probability that both the balls are white is:

Question

Smart Achievers · Accepted Answer

(3)

Ans. $\frac{1}{12}$

Explanation:

$Required probability = \frac{{}^{3}C_{2}}{{}^{9}C_{2}} = \frac{1}{12}$

Solution

Q.
A bag contains 3 white, 4 black and 2 red balls. If 2 balls are drawn at random (without replacement), then the probability that both the balls are white is:

1 $\frac{1}{18}$

2 $\frac{1}{36}$

3 $\frac{1}{12}$

4 $\frac{1}{24}$

Ans.
(3)

Ans. $\frac{1}{12}$

Explanation:

$Required probability = \frac{{}^{3}C_{2}}{{}^{9}C_{2}} = \frac{1}{12}$

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Solution

Q. A bag contains 3 white, 4 black and 2 red balls. If 2 balls are drawn at random (without replacement), then the probability that both the balls are white is:

1 118

2 136

3 112

4 124

Ans. (3) Ans. 112 Explanation: Required probability=C23C29=112