The wavelength of photon ‘A’ is 400 nm. The frequency of photon ‘B’ is 10 16 s - 1 . The wave number of photon ‘C’ is 10 4 c m - 1 . The correct order of energy of these photons is: [2026]

Question

The wavelength of photon ‘A’ is 400 nm. The frequency of photon ‘B’ is $10^{16} s^{- 1}$ . The wave number of photon ‘C’ is $10^{4} c m^{- 1}$ . The correct order of energy of these photons is: [2026]

Smart Achievers · Accepted Answer

(4)

$(1) Wavelength of A = 400 nm$

$(2) Wavelength of B (λ) = \frac{c}{ν} = \frac{3 \times 10^{8}}{10^{16}} = 3 \times 10^{- 8} = 30 \times 10^{- 9} = 30 nm$

$(3) Wavelength of C (λ) = \frac{1}{\bar{ν}} = \frac{1}{10^{4}} = 10^{- 4} cm = 10^{- 6} m = 1000 nm$

$Here λ_{C} > λ_{A} > λ_{B}$

$Energy (E) \propto \frac{1}{λ}$

$So E_{B} > E_{A} > E_{C}$

$Ans. (4) is correct.$

Solution

Q.
The wavelength of photon ‘A’ is 400 nm. The frequency of photon ‘B’ is $10^{16} s^{- 1}$ . The wave number of photon ‘C’ is $10^{4} c m^{- 1}$ . The correct order of energy of these photons is: [2026]

1 A > B > C

2 C > B > A

3 A > C > B

4 B > A > C

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