The ionization energy of sodium in kJ , if electromagnetic radiation of wavelength 242 nm is just sufficient to ionize sodium atom is

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Solution

Q.
The ionization energy of sodium in kJ $m o l^{- 1}$ , if electromagnetic radiation of wavelength 242 nm is just sufficient to ionize sodium atom is ________ . [2024]

Ans.
(494) Energy of photon $E_{p}$ is :

   $E_{p} = \frac{h c}{λ} = \frac{6.626 \times 10^{- 34} Js \times 3 \times 10^{8} {ms}^{- 1}}{242 \times 10^{- 9} m}$

lonization energy of one atom of sodium

$= Energy of one photon = \frac{6.626 \times 10^{- 34} \times 3 \times 10^{8}}{242 \times 10^{- 9}} J$

  Ionization energy of one mol of sodium atoms

   $= \frac{6.626 \times 10^{- 34} \times 3 \times 10^{8}}{242 \times 10^{- 9}} \times 6.022 \times 10^{23} \times \frac{1}{1000} kJ$

   $= 494.65 {kJmol}^{- 1}$

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