Q.

The value of C450+∑r=16C356-r is

1 C456  
2 C356  
3 C355  
4 C455  

Ans.

(1)

C450+∑r=16C356-r

Putting r=6, 5, 4, 3, 2, 1, we get

C450+C350+C351+C352+C353+C354+C355                  (∵ Crn+Cr+1n=Cr+1n+1)

=C451+C351+C352+C353+C354+C355    

=C452+C352+C353+C354+C355

=C453+C353+C354+C355

=C454+C354+C355

=C455+C355=C456