The value of C450+∑r=16C356-r is
(1)
C450+∑r=16C356-r
Putting r=6, 5, 4, 3, 2, 1, we get
C450+C350+C351+C352+C353+C354+C355 (∵ Crn+Cr+1n=Cr+1n+1)
=C451+C351+C352+C353+C354+C355
=C452+C352+C353+C354+C355
=C453+C353+C354+C355
=C454+C354+C355
=C455+C355=C456